# Angles in Parallel Lines Test-1

Angles in Parallel Lines Test-1, we can act towards the solution with any of the angles formed by the interior opposite-contrast-opposite-external reverse angles, that is, two parallel lines and a line that intersects them. The most common of these is the interior reverse angles (z rule).

With the angles between parallel lines, rules such as M-zigzag-pencil tip are defined. These rules emerge from the angles we mentioned at the beginning. We can obtain quick solutions by applying them to problems.

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You can review the images, from the end of the page 7.-8.-9 class in **PDF** format. You can download angles in parallel lines test-1 file to your computer.

## Angles in Parallel lines Test-1 Problems

**Problem 1 :**

In the figure, A, B, C points are linear, complementary of 1/3 of m (EBA) m (CBD); if m (CBD) = m (DBE) + 10 °; How many degrees is m (DBE)?

**Problem 2 :**

[FG parallel [BA, [FE] parallel [CD], if m (DCB) = 130 °, m (ABC) = 4x-10 °, m (EFG) = 3x; How many degrees is x?

**Problem 3 :**

FK parallel [CR, [CP parallel [DA], [AE] parallel [CE], if 3m (RCE) =2m (DAE) =m (EBA) = x; How many degrees is x?

**Problem 4 :**

[BA parallel [EF parallel HG, [AE] parallel [CE], İf m (ABC) = m (EDC), m (DEF) = 100 °, m (DCB) = x; How many degrees is x?

**Problem 5 :**

[BE parallel [CF, if m (ABE) = 150 °, m (BAD) = 60 °, m (ADC) = 50 °; How many degrees is m (FCD) = x?

**Problem 6 :**

[AF parallel [DE, [AC] perpendicular [BD], [AC] bisector, if m (BDE) = 145 °; How many degrees is m (DBA) = x?

**Problem 7 :**

If FE parallel [CD, m (GAE) = 5y-5 °, m (DCB) = 3y + 5 °, m (GBC) = 60 °; How many degrees is m (FAB) = x?

**Problem 8 :**

[BA parallel [FD, [KP parallel [BE, m (EBA) = 120º, if m (FKP) = 105º; How many degrees is m (CFK) = x?

## Angles in Parallel lines Test-1 Solutions

**Solution of Problem 1 :**

Test with direct angles solution for beginners

**Solution of Problem 2 :**

Let the line segment that we will draw from point C are parallel to the lines given in the question. The desired angle measurement is obtained from the equation of congruent angles m (DCK) = 3x, alternate angles m (KCB) = 4x-10 °, from here 3x + 4x-10 ° = 130 °. x angle is 20 °.

**Solution of Problem 3 :**

The most practical solution to this question of the angles in the line test would be to see the parallel angles of the road sides or the opposite parallel angles.

**Solution of Problem 4 :**

With the inside angles and the m rule, the desired angle x has a dimension of 100 °.

**Solution of Problem 5 :**

Solution: If we intersect the extension [AB] and [CD] at one point, we find the angle x with the rule m since the third angle of the triangle is also known.

**Solution of Problem 6 :**

The bisectors of the opposite state angles form a right angle. We can immediately write x on the angle between the parallel we have drawn [BK].

**Solution of Problem 7 :**

If we add the angles between parallel lines and equate them to 360 ° (pencil point rule), then y = 30 °, from the right angle x = 35 °.

**Solution of Problem 8 :**

Write m (ECF) = 120 ° from directional angles, 120 ° + 360 ° -x + 105 ° = 360 ° from pencil rule, measure of angle x is 225 °.

### Angles in Parallel Lines Test-1 PDF

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