 # Angles in Parallel Lines Test-1

Angles in Parallel Lines Test-1, we can act towards the solution with any of the angles formed by the interior opposite-contrast-opposite-external reverse angles, that is, two parallel lines and a line that intersects them. The most common of these is the interior reverse angles (z rule).

With the angles between parallel lines, rules such as M-zigzag-pencil tip are defined. These rules emerge from the angles we mentioned at the beginning. We can obtain quick solutions by applying them to problems.

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You can review the images, from the end of the page 7.-8.-9 class in PDF format. You can download angles in parallel lines test-1 file to your computer.

## Angles in Parallel lines Test-1 Problems

Problem 1 :

In the figure, A, B, C points are linear, complementary of 1/3 of m (EBA) m (CBD); if m (CBD) = m (DBE) + 10 °; How many degrees is m (DBE)?

Problem 2 :

[FG parallel [BA, [FE] parallel [CD], if m (DCB) = 130 °, m (ABC) = 4x-10 °, m (EFG) = 3x; How many degrees is x?

Problem 3 :

FK parallel [CR, [CP parallel [DA], [AE] parallel [CE], if 3m (RCE) =2m (DAE) =m (EBA) = x; How many degrees is x?

Problem 4 :

[BA parallel [EF parallel HG, [AE] parallel [CE], İf m (ABC) = m (EDC), m (DEF) = 100 °, m (DCB) = x; How many degrees is x?

Problem 5 :

[BE parallel [CF, if m (ABE) = 150 °, m (BAD) = 60 °, m (ADC) = 50 °; How many degrees is m (FCD) = x?

Problem 6 :

[AF parallel [DE, [AC] perpendicular [BD], [AC] bisector, if m (BDE) = 145 °; How many degrees is m (DBA) = x?

Problem 7 :

If FE parallel [CD, m (GAE) = 5y-5 °, m (DCB) = 3y + 5 °, m (GBC) = 60 °; How many degrees is m (FAB) = x?

Problem 8 :

[BA parallel [FD, [KP parallel [BE, m (EBA) = 120º, if m (FKP) = 105º; How many degrees is m (CFK) = x?

## Angles in Parallel lines Test-1 Solutions

Solution of Problem 1 :

Test with direct angles solution for beginners

Solution of Problem 2 :

Let the line segment that we will draw from point C are parallel to the lines given in the question. The desired angle measurement is obtained from the equation of congruent angles m (DCK) = 3x, alternate angles m (KCB) = 4x-10 °, from here 3x + 4x-10 ° = 130 °. x angle is 20 °.

Solution of Problem 3 :

The most practical solution to this question of the angles in the line test would be to see the parallel angles of the road sides or the opposite parallel angles.

Solution of Problem 4 :

With the inside angles and the m rule, the desired angle x has a dimension of 100 °.

Solution of Problem 5 :

Solution: If we intersect the extension [AB] and [CD] at one point, we find the angle x with the rule m since the third angle of the triangle is also known.

Solution of Problem 6 :

The bisectors of the opposite state angles form a right angle. We can immediately write x on the angle between the parallel we have drawn [BK].

Solution of Problem 7 :

If we add the angles between parallel lines and equate them to 360 ° (pencil point rule), then y = 30 °, from the right angle x = 35 °.

Solution of Problem 8 :

Write m (ECF) = 120 ° from directional angles, 120 ° + 360 ° -x + 105 ° = 360 ° from pencil rule, measure of angle x is 225 °.

### Angles in Parallel Lines Test-1 PDF

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