special right triangles test 2

Special Right Triangles Test-2

special right triangles

Special Right Triangles Test-2 … 30 60 90 triangle questions, 45 45 90 triangle questions, 15 75 90 triangle questions, center of perpendicularity questions, magnificent triple questions, special triangle questions, Pythagoras relation questions, 30 60 90 triangle solutions, orthogonal center questions, 15 75 Solving 90 triangle questions, Pythagoras solution questions

Special Right Triangles Test-2 Problems

Problem 1 :

30 60 90 triangle

If ABC is a triangle, [BA] perpendicular [AC], | AD | = | BE | = | EC |, if m (CBA) = 30 °; How many degrees is m (DCE) = α?

Problem 2 :

ABC is a triangle, if [PA] perpendicular [AC], m (BAP) = 15 °, m (ACP) = 25 °; | PC | / | AB | What is the rate?

median of a right triangle

Problem 3 :

ABC is a triangle, [BK] perpendicular [AC], | BL | = | LC |, | BK | = | AL | if; How many degrees is m (LAC) = x?

özel üçgen soru

Problem 4 :

If point E on [BD] is the orthocenter of triangle ABC, | BE | = 4k root3 cm, | ED | = root3 cm, m (ACB) = 60 °; | AC | = how many cm is x?

orthocenter of triangles

Problem 5 :

If ABC right triangle, [BA] perpendicular [AC], [AE] perpendicular [BC], | BD | = | DC |, | AD | = 10 cm, m (ACB) = 15 °; | AE | = how many cm is x?

15 75 90 üçgeni soruları

Problem 6 :

If ABC is a triangle, [DA] perpendicular [AC], m (BAD) = 45 °, | AD | = root2 cm, | AC | = 2 root2 cm; | AB | = how many cm is x?

45 45 90 üçgeni ile ilgili sorular

Problem 7 :

If points A, D and E are linear, [AE] perpendicular [BC], | AD | = 7 cm, | AC | = 8 cm, | BD | = 3 cm in triangle ABC; | DC | = how many cm is x?

pisagor bağıntısı soruları

Problem 8 :

ABC and CBD are a triangle each, [AB] perpendicular [BD], | CB | = | CD |, | AC | = | BD | if; How many degrees is m (BAC) = x?

kenarlarına göre özel üçgen soruları

Special Right Triangle Test-2 Solutions

Solution of Problem 1 :

If we call the hypotenuse length 2 br in ABC triangle (30 60 90), the side opposite 30 ° is 1 br. The ABC triangle becomes isosceles (45 45 90), since α + 45 ° = 60 °, α = 15 °.

dik ve özel üçgenler test2 çözümleri

Solution of Problem 2 :

The measure of angle B from the sum of the angles of triangle ABC is 50 °. If we draw a median of the hypotenuse in the right triangle APC, the median length of the hypotenuse is equal to half the hypotenuse (perfect triple-super triple). Accordingly, m (ASB) = 50 ° in the ABS triangle. AB | = | AS | then | PC | / | AB | rate is 2.

muhteşem üçlü soru çözümü

Solution of Problem 3 :

Since the base of triangle ABC is divided into two equal parts, the ratio of parallel similar triangles we will draw makes 2, so that the hypotenuse in the right triangle ALM is 2 times the vertical side. The angle x angle of the corner opposite this right side will be 30 °.

30 60 90 üçgeni çözümlü sorular

Solution of Problem 4 :

If point E is the orthocenter of perpendicularity in triangle ABC, [BD] is perpendicular to [AC]. If we draw a line from corner A so that it passes through point E, it will cross [BC] perpendicularly.

The altitude of a triangle is a line through a given vertex of the triangle and perpendicular to the side opposite to the vertex. For any triangle, all three altitudes intersect at a point called the orthocenter which may be inside or outside the triangle.

diklik merkezi soru çözümü

Solution of Problem 5 :

Since ABC is the median of right triangle [BD], | BC | = 20 cm. Since ABC is a 15 75 90 triangle, the height of the hypotenuse is one quarter of the hypotenuse, so the height = x = 5 cm. (Proven)

15 75 90 üçgeni soru çözümü

Solution of Problem 6 :

Let’s draw parallel to AB from point D in triangle ABC. Since the triangle of AED will be an isosceles right triangle, AD is root2 and the length of DE from similar triangles formed is the middle of the USA triangle. Since the length of AED is 2 cm, AB length is 4 cm.

dik üçgen soruları çözümlü

Solution of Problem 7 :

If we take the symmetry of the BDC triangle in the ABC triangle, an ABFC quadrilateral whose diagonals intersect perpendicularly is 7² + x² = 8² + 3². From here, x = 2 root6 is found. (Proven)

pisagor çözümlü sorular

Solution of Problem 8 :

In an isosceles triangle, the height of the base is also the median. If we say | BE | = | ED | = a cm, from the FBEC rectangle, | BE | = | FC | = a cm. The hypotenuse in the AFC right triangle | FC | Since it is twice of, the measure of the angle x is 30°.

30 60 90 üçgeni çözümlü örnek

geometry pdf

Special Right Triangles Test-2 PDF

Course Geometry offers Geometry textbook in pdf format that can be downloaded free of charge. Students can view the special right triangles test-2 pdf, which is important for university entrance exam, which aims to improve students’ problem solving skills

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